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Re: Vertex fitters' problems [message #15023 is a reply to message #15019] |
Fri, 26 July 2013 13:26 |
StefanoSpataro
Messages: 2736 Registered: June 2005 Location: Torino
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first-grade participant |
From: 2.235.190*
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Very interesting...
root [0] TVector3 e(1,2,3)
root [1] TVector3 f=(1,2,3)
root [2] e.Print()
TVector3 A 3D physics vector (x,y,z)=(1.000000,2.000000,3.000000) (rho,theta,phi)=(3.741657,36.699225,63.434949)
root [3] f.Print()
TVector3 A 3D physics vector (x,y,z)=(3.000000,0.000000,0.000000) (rho,theta,phi)=(3.000000,90.000000,0.000000)
root [4] TVector3 d
root [5] d=(1,2,3)
(class TVector3)41869040
root [6] d.Print()
TVector3 A 3D physics vector (x,y,z)=(3.000000,0.000000,0.000000) (rho,theta,phi)=(3.000000,90.000000,0.000000)
and without a single complain...
[Updated on: Fri, 26 July 2013 14:42] Report message to a moderator
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