GSI Forum
GSI Helmholtzzentrum für Schwerionenforschung

Home » PANDA » PandaRoot » MVD » Energy loss in MVD
Energy loss in MVD [message #10201] Fri, 12 February 2010 20:10 Go to previous message
StefanoSpataro is currently offline  StefanoSpataro
Messages: 2736
Registered: June 2005
Location: Torino
first-grade participant

From: *56-82-r.retail.telecomitalia.it
Dear all,
Laura has fixed the calculation of the reconstructed dE/dx in PndPidCorrelator class. You can try to run macro/pid macros and to plot the dE/dx from PidCandidate.

If I shoot the detector with 1GeV/c muons, I have the following dE/dx distribution:

index.php?t=getfile&id=5846&private=0

(unity: GeV/cm).
Just fitting the distribution with a landau (as it should be), we obtain the following values:

MPV: 2.83 MeV/cm
sig: 0.23 MeV/cm


If we consider the silicon density rho = 2.33 g/cm^3
-> dE/dx ~ 1.21 [MeV cm^2 / g]

I would like to ask to MVD experts how much is the "theoretical value", I would suppose you have already some tables with the correct values.
We have also compared the reconstructed dE/dx with the MonteCarlo value, and the results seem in agreement, but I would like to know what is coming from "physics" before believing blindly in simulation.

Thanks in advance.
  • Attachment: mvd_dedx.gif
    (Size: 14.74KB, Downloaded 533 times)
 
Read Message
Read Message
Previous Topic: Riemann fit in MVD?
Next Topic: New MVD Geometry
Goto Forum:
  


Current Time: Mon Oct 18 17:17:46 CEST 2021

Total time taken to generate the page: 0.01974 seconds