invariant mass [message #16028] |
Tue, 25 March 2014 10:26 |
ForamShah
Messages: 25 Registered: March 2014 Location: india
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continuous participant |
From: 14.139.121*
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hello,
i want to know the exact method to find invariant mass and for that what changes i have to make and where(simulation file ,analysis file...)??
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Re: invariant mass [message #16031 is a reply to message #16029] |
Tue, 25 March 2014 10:43 |
Elisabetta Prencipe (2)
Messages: 214 Registered: February 2013
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first-grade participant |
From: *ikp.kfa-juelich.de
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Dear Foram Shah,
just one comment more to the Stefano reply, to make your life easier with PandaRoot simulations: if you are using the macros of the tutorial, what basically you have to change is the beam momentum (beginning of the simulation macro: make sure it is properly set up for the production of the X(3872)), and you should change also the file.dec where you set up the decay file of your interest (always in the simulation macro). I assume here you will use EvtGen as MC generator. Then, the digi-, rec-, pid-, macros can be run just like they are in the tutorial. Of course, you have to change the analysis macro of the tutorial: it is right now set up for the example provided in the page that Stefano pointed you: ppbar ---> psi--->Jpsi pi+ pi-.
If you wish to try ppbar ---> X(3872) ---> Jpsi pi+ pi-, it is not so much change, in the end. The analysis macro shows you how to calculate invariant mass, momentum, how to use the fitters.
cheers, Elisabetta
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Re: invariant mass [message #16037 is a reply to message #16034] |
Tue, 25 March 2014 11:06 |
Elisabetta Prencipe (2)
Messages: 214 Registered: February 2013
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first-grade participant |
From: *ikp.kfa-juelich.de
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Hi Foram (my miseducation: I hope this is your first name),
the window around the nominal mass of J/psi it's up to you. In that example the window is pretty large: +/- 1 GeV/c2. You can try 0.1 or 0.2, for instance. You will learn by doing.
cheers, Elisabetta
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